Linear Equations Reference

Inequalities

An inequality describes a range of values instead of one exact value. The main skill is preserving the direction of the inequality while rewriting it.

Solved Examples

Jump directly to a worked example by inequality type.

Fact Table

TypeMethodReminder
Linear inequalitySolve like an equation.Flip the sign when multiplying or dividing by a negative.
Compound "and"Both conditions must be true.The graph is the overlap.
Compound "or"At least one condition must be true.The graph is the union.
Absolute value less thanRewrite as a bounded interval.$|u|\lt a$ means $-a\lt u\lt a$.
Absolute value greater thanSplit into two outside cases.$|u|\gt a$ means $u\lt -a$ or $u\gt a$.
Polynomial or rational inequalityUse a sign chart.Critical numbers split the number line into test intervals.

Content Formulas

Flip Rule
$$-2x\lt 8\quad \Longrightarrow \quad x\gt -4$$
Interval Notation
$$a\lt x\lt b\quad \Longrightarrow \quad (a,b)$$
Absolute Value Inside
$$|u|\lt a\quad \Longrightarrow \quad -a\lt u\lt a$$
Absolute Value Outside
$$|u|\gt a\quad \Longrightarrow \quad u\lt -a\ \text{or}\ u\gt a$$
Open circles match $<$ and $>$. Closed circles match $\le$ and $\ge$.

Classic Examples

Linear Inequality

Solve $-3x+5\le 17$.

Solution Steps
  1. Subtract $5$ from both sides.
  2. Divide by $-3$ and reverse the inequality sign.
  3. State the solution in interval notation: $[-4,\infty)$.
$$-3x\le 12$$$$x\ge -4$$$$[-4,\infty)$$

Compound Inequality

Solve $-2\lt 3x+1\le 10$.

Solution Steps
  1. Subtract $1$ from all three parts.
  2. Divide all three parts by $3$.
  3. State the solution in interval notation: $(-1,3]$.
$$-3\lt 3x\le 9$$$$-1\lt x\le 3$$$$(-1,3]$$

Absolute Value Less Than

Solve $|2x-1|\lt 7$.

Solution Steps
  1. Rewrite the absolute-value inequality as a compound inequality.
  2. Add $1$ to all three parts.
  3. Divide all three parts by $2$ and state the interval.
$$-7\lt 2x-1\lt 7$$$$-6\lt 2x\lt 8$$$$-3\lt x\lt 4$$

Absolute Value Greater Than

Solve $|x+2|\ge 5$.

Solution Steps
  1. Rewrite the absolute-value inequality as two outside cases.
  2. Solve both linear inequalities.
  3. Join the two regions with union notation.
$$x+2\le -5\quad \text{or}\quad x+2\ge 5$$$$x\le -7\quad \text{or}\quad x\ge 3$$$$(-\infty,-7]\cup[3,\infty)$$

Quadratic Sign Chart

Solve $(x-2)(x+3)\gt 0$.

Solution Steps
  1. Find the critical numbers by setting each factor equal to zero.
  2. Test the sign on the interval to the left of $-3$.
  3. Test the sign on the interval between $-3$ and $2$.
  4. Test the sign on the interval to the right of $2$.
  5. Select the positive intervals and state the solution.
$$x=-3,\quad x=2$$$$(-\infty,-3):\ (+)$$$$(-3,2):\ (-)$$$$(2,\infty):\ (+)$$$$(-\infty,-3)\cup(2,\infty)$$