Numbers and Polynomials Reference

Complex Numbers

Complex numbers extend the real number system so every quadratic equation has solutions.

Solved Examples

Jump directly to a worked example by operation or equation type.

Fact Table

IdeaRuleWatch For
Imaginary unit$i^2=-1$.Replace every $i^2$ with $-1$.
Standard form$a+bi$, where $a$ and $b$ are real.Combine real parts with real parts and imaginary parts with imaginary parts.
Conjugates$a+bi$ and $a-bi$.Their product is the real number $a^2+b^2$.
Powers of $i$$i, -1, -i, 1$ repeats every four powers.Reduce the exponent modulo $4$.

Content Formulas

Product
$$(a+bi)(c+di)=(ac-bd)+(ad+bc)i$$
Conjugate Product
$$(a+bi)(a-bi)=a^2+b^2$$
Quadratic Formula
$$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$$

Classic Examples

Add Complex Numbers

Simplify $(3+2i)+(4-5i)$.

Solution Steps
  1. Group the real parts and the imaginary parts.
  2. Add each pair.
  3. State the result in standard form.
$$(3+4)+(2i-5i)$$$$7-3i$$$$\boxed{7-3i}$$

Multiply Complex Numbers

Simplify $(2+i)(3-4i)$.

Solution Steps
  1. Distribute each term in the first factor.
  2. Replace $i^2$ with $-1$.
  3. Combine the real and imaginary parts.
$$6-8i+3i-4i^2$$$$6-5i+4$$$$\boxed{10-5i}$$

Simplify a Power of $i$

Simplify $i^{37}$.

Solution Steps
  1. Divide the exponent by the cycle length $4$.
  2. Use the remainder to identify the matching power.
  3. State the simplified value.
$$37=4(9)+1$$$$i^{37}=\left(i^4\right)^9i$$$$\boxed{i^{37}=i}$$

Solve a Quadratic with Nonreal Roots

Solve $x^2+4x+13=0$.

Solution Steps
  1. Use the quadratic formula with $a=1$, $b=4$, and $c=13$.
  2. Simplify the negative discriminant using $\sqrt{-36}=6i$.
  3. Reduce the fractions and state both roots.
$$x=\frac{-4\pm\sqrt{4^2-4(1)(13)}}{2}$$$$x=\frac{-4\pm\sqrt{-36}}{2}=\frac{-4\pm6i}{2}$$$$\boxed{x=-2\pm3i}$$