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Precalculus / Trigonometry / Unit Circle

Trigonometry Reference

Unit Circle

On the unit circle, a point has coordinates $(\cos\theta,\sin\theta)$. This page keeps the core values visible without trying to become the full interactive lab yet.

Fact Table

Quadrant Angle Range Signs
I $0^\circ$ to $90^\circ$ $\sin\theta>0,\ \cos\theta>0,\ \tan\theta>0$
II $90^\circ$ to $180^\circ$ $\sin\theta>0,\ \cos\theta<0,\ \tan\theta<0$
III $180^\circ$ to $270^\circ$ $\sin\theta<0,\ \cos\theta<0,\ \tan\theta>0$
IV $270^\circ$ to $360^\circ$ $\sin\theta<0,\ \cos\theta>0,\ \tan\theta<0$

Content Formulas

Unit Circle Point
$$(x,y)=(\cos\theta,\sin\theta)$$
Tangent
$$\tan\theta=\frac{\sin\theta}{\cos\theta}=\frac yx,\quad x\ne0$$
Remember the first-quadrant reference values, then use quadrant signs to place them around the circle.

Common Values

Degrees Radians $\cos\theta$ $\sin\theta$
$0^\circ$ $0$ $1$ $0$
$30^\circ$ $\frac{\pi}{6}$ $\frac{\sqrt3}{2}$ $\frac12$
$45^\circ$ $\frac{\pi}{4}$ $\frac{\sqrt2}{2}$ $\frac{\sqrt2}{2}$
$60^\circ$ $\frac{\pi}{3}$ $\frac12$ $\frac{\sqrt3}{2}$
$90^\circ$ $\frac{\pi}{2}$ $0$ $1$

Classic Examples

Coordinates from an Angle

Find the unit-circle point for $150^\circ$.

Solution StrategyThe reference angle is $30^\circ$, and $150^\circ$ is in Quadrant II.
$$150^\circ=180^\circ-30^\circ$$ $$\cos150^\circ=-\frac{\sqrt3}{2}$$ $$\sin150^\circ=\frac12$$ $$\left(-\frac{\sqrt3}{2},\frac12\right)$$

Find Tangent

Find $\tan(225^\circ)$.

Solution StrategyThe reference angle is $45^\circ$, and tangent is positive in Quadrant III.
$$225^\circ=180^\circ+45^\circ$$ $$\tan(225^\circ)=1$$